import numpy as np
import pytest
import pandas as pd
from pandas import Index, PeriodIndex, date_range, period_range
import pandas.core.indexes.period as period
import pandas.util.testing as tm
def _permute(obj):
return obj.take(np.random.permutation(len(obj)))
class TestPeriodIndex(object):
def test_joins(self, join_type):
index = period_range('1/1/2000', '1/20/2000', freq='D')
joined = index.join(index[:-5], how=join_type)
assert isinstance(joined, PeriodIndex)
assert joined.freq == index.freq
def test_join_self(self, join_type):
index = period_range('1/1/2000', '1/20/2000', freq='D')
res = index.join(index, how=join_type)
assert index is res
def test_join_does_not_recur(self):
df = tm.makeCustomDataframe(
3, 2, data_gen_f=lambda *args: np.random.randint(2),
c_idx_type='p', r_idx_type='dt')
s = df.iloc[:2, 0]
res = s.index.join(df.columns, how='outer')
expected = Index([s.index[0], s.index[1],
df.columns[0], df.columns[1]], object)
tm.assert_index_equal(res, expected)
@pytest.mark.parametrize("sort", [None, False])
def test_union(self, sort):
# union
other1 = pd.period_range('1/1/2000', freq='D', periods=5)
rng1 = pd.period_range('1/6/2000', freq='D', periods=5)
expected1 = pd.period_range('1/1/2000', freq='D', periods=10)
rng2 = pd.period_range('1/1/2000', freq='D', periods=5)
other2 = pd.period_range('1/4/2000', freq='D', periods=5)
expected2 = pd.period_range('1/1/2000', freq='D', periods=8)
rng3 = pd.period_range('1/1/2000', freq='D', periods=5)
other3 = pd.PeriodIndex([], freq='D')
expected3 = pd.period_range('1/1/2000', freq='D', periods=5)
rng4 = pd.period_range('2000-01-01 09:00', freq='H', periods=5)
other4 = pd.period_range('2000-01-02 09:00', freq='H', periods=5)
expected4 = pd.PeriodIndex(['2000-01-01 09:00', '2000-01-01 10:00',
'2000-01-01 11:00', '2000-01-01 12:00',
'2000-01-01 13:00', '2000-01-02 09:00',
'2000-01-02 10:00', '2000-01-02 11:00',
'2000-01-02 12:00', '2000-01-02 13:00'],
freq='H')
rng5 = pd.PeriodIndex(['2000-01-01 09:01', '2000-01-01 09:03',
'2000-01-01 09:05'], freq='T')
other5 = pd.PeriodIndex(['2000-01-01 09:01', '2000-01-01 09:05'
'2000-01-01 09:08'],
freq='T')
expected5 = pd.PeriodIndex(['2000-01-01 09:01', '2000-01-01 09:03',
'2000-01-01 09:05', '2000-01-01 09:08'],
freq='T')
rng6 = pd.period_range('2000-01-01', freq='M', periods=7)
other6 = pd.period_range('2000-04-01', freq='M', periods=7)
expected6 = pd.period_range('2000-01-01', freq='M', periods=10)
rng7 = pd.period_range('2003-01-01', freq='A', periods=5)
other7 = pd.period_range('1998-01-01', freq='A', periods=8)
expected7 = pd.period_range('1998-01-01', freq='A', periods=10)
rng8 = pd.PeriodIndex(['1/3/2000', '1/2/2000', '1/1/2000',
'1/5/2000', '1/4/2000'], freq='D')
other8 = pd.period_range('1/6/2000', freq='D', periods=5)
expected8 = pd.PeriodIndex(['1/3/2000', '1/2/2000', '1/1/2000',
'1/5/2000', '1/4/2000', '1/6/2000',
'1/7/2000', '1/8/2000', '1/9/2000',
'1/10/2000'], freq='D')
for rng, other, expected in [(rng1, other1, expected1),
(rng2, other2, expected2),
(rng3, other3, expected3),
(rng4, other4, expected4),
(rng5, other5, expected5),
(rng6, other6, expected6),
(rng7, other7, expected7),
(rng8, other8, expected8)]:
result_union = rng.union(other, sort=sort)
if sort is None:
expected = expected.sort_values()
tm.assert_index_equal(result_union, expected)
@pytest.mark.parametrize("sort", [None, False])
def test_union_misc(self, sort):
index = period_range('1/1/2000', '1/20/2000', freq='D')
result = index[:-5].union(index[10:], sort=sort)
tm.assert_index_equal(result, index)
# not in order
result = _permute(index[:-5]).union(_permute(index[10:]), sort=sort)
if sort is None:
tm.assert_index_equal(result, index)
assert tm.equalContents(result, index)
# raise if different frequencies
index = period_range('1/1/2000', '1/20/2000', freq='D')
index2 = period_range('1/1/2000', '1/20/2000', freq='W-WED')
with pytest.raises(period.IncompatibleFrequency):
index.union(index2, sort=sort)
msg = 'can only call with other PeriodIndex-ed objects'
with pytest.raises(ValueError, match=msg):
index.join(index.to_timestamp())
index3 = period_range('1/1/2000', '1/20/2000', freq='2D')
with pytest.raises(period.IncompatibleFrequency):
index.join(index3)
def test_union_dataframe_index(self):
rng1 = pd.period_range('1/1/1999', '1/1/2012', freq='M')
s1 = pd.Series(np.random.randn(len(rng1)), rng1)
rng2 = pd.period_range('1/1/1980', '12/1/2001', freq='M')
s2 = pd.Series(np.random.randn(len(rng2)), rng2)
df = pd.DataFrame({'s1': s1, 's2': s2})
exp = pd.period_range('1/1/1980', '1/1/2012', freq='M')
tm.assert_index_equal(df.index, exp)
@pytest.mark.parametrize("sort", [None, False])
def test_intersection(self, sort):
index = period_range('1/1/2000', '1/20/2000', freq='D')
result = index[:-5].intersection(index[10:], sort=sort)
tm.assert_index_equal(result, index[10:-5])
# not in order
left = _permute(index[:-5])
right = _permute(index[10:])
result = left.intersection(right, sort=sort)
if sort is None:
tm.assert_index_equal(result, index[10:-5])
assert tm.equalContents(result, index[10:-5])
# raise if different frequencies
index = period_range('1/1/2000', '1/20/2000', freq='D')
index2 = period_range('1/1/2000', '1/20/2000', freq='W-WED')
with pytest.raises(period.IncompatibleFrequency):
index.intersection(index2, sort=sort)
index3 = period_range('1/1/2000', '1/20/2000', freq='2D')
with pytest.raises(period.IncompatibleFrequency):
index.intersection(index3, sort=sort)
@pytest.mark.parametrize("sort", [None, False])
def test_intersection_cases(self, sort):
base = period_range('6/1/2000', '6/30/2000', freq='D', name='idx')
# if target has the same name, it is preserved
rng2 = period_range('5/15/2000', '6/20/2000', freq='D', name='idx')
expected2 = period_range('6/1/2000', '6/20/2000', freq='D',
name='idx')
# if target name is different, it will be reset
rng3 = period_range('5/15/2000', '6/20/2000', freq='D', name='other')
expected3 = period_range('6/1/2000', '6/20/2000', freq='D',
name=None)
rng4 = period_range('7/1/2000', '7/31/2000', freq='D', name='idx')
expected4 = PeriodIndex([], name='idx', freq='D')
for (rng, expected) in [(rng2, expected2), (rng3, expected3),
(rng4, expected4)]:
result = base.intersection(rng, sort=sort)
tm.assert_index_equal(result, expected)
assert result.name == expected.name
assert result.freq == expected.freq
# non-monotonic
base = PeriodIndex(['2011-01-05', '2011-01-04', '2011-01-02',
'2011-01-03'], freq='D', name='idx')
rng2 = PeriodIndex(['2011-01-04', '2011-01-02',
'2011-02-02', '2011-02-03'],
freq='D', name='idx')
expected2 = PeriodIndex(['2011-01-04', '2011-01-02'], freq='D',
name='idx')
rng3 = PeriodIndex(['2011-01-04', '2011-01-02', '2011-02-02',
'2011-02-03'],
freq='D', name='other')
expected3 = PeriodIndex(['2011-01-04', '2011-01-02'], freq='D',
name=None)
rng4 = period_range('7/1/2000', '7/31/2000', freq='D', name='idx')
expected4 = PeriodIndex([], freq='D', name='idx')
for (rng, expected) in [(rng2, expected2), (rng3, expected3),
(rng4, expected4)]:
result = base.intersection(rng, sort=sort)
if sort is None:
expected = expected.sort_values()
tm.assert_index_equal(result, expected)
assert result.name == expected.name
assert result.freq == 'D'
# empty same freq
rng = date_range('6/1/2000', '6/15/2000', freq='T')
result = rng[0:0].intersection(rng)
assert len(result) == 0
result = rng.intersection(rng[0:0])
assert len(result) == 0
@pytest.mark.parametrize("sort", [None, False])
def test_difference(self, sort):
# diff
period_rng = ['1/3/2000', '1/2/2000', '1/1/2000', '1/5/2000',
'1/4/2000']
rng1 = pd.PeriodIndex(period_rng, freq='D')
other1 = pd.period_range('1/6/2000', freq='D', periods=5)
expected1 = rng1
rng2 = pd.PeriodIndex(period_rng, freq='D')
other2 = pd.period_range('1/4/2000', freq='D', periods=5)
expected2 = pd.PeriodIndex(['1/3/2000', '1/2/2000', '1/1/2000'],
freq='D')
rng3 = pd.PeriodIndex(period_rng, freq='D')
other3 = pd.PeriodIndex([], freq='D')
expected3 = rng3
period_rng = ['2000-01-01 10:00', '2000-01-01 09:00',
'2000-01-01 12:00', '2000-01-01 11:00',
'2000-01-01 13:00']
rng4 = pd.PeriodIndex(period_rng, freq='H')
other4 = pd.period_range('2000-01-02 09:00', freq='H', periods=5)
expected4 = rng4
rng5 = pd.PeriodIndex(['2000-01-01 09:03', '2000-01-01 09:01',
'2000-01-01 09:05'], freq='T')
other5 = pd.PeriodIndex(
['2000-01-01 09:01', '2000-01-01 09:05'], freq='T')
expected5 = pd.PeriodIndex(['2000-01-01 09:03'], freq='T')
period_rng = ['2000-02-01', '2000-01-01', '2000-06-01',
'2000-07-01', '2000-05-01', '2000-03-01',
'2000-04-01']
rng6 = pd.PeriodIndex(period_rng, freq='M')
other6 = pd.period_range('2000-04-01', freq='M', periods=7)
expected6 = pd.PeriodIndex(['2000-02-01', '2000-01-01', '2000-03-01'],
freq='M')
period_rng = ['2003', '2007', '2006', '2005', '2004']
rng7 = pd.PeriodIndex(period_rng, freq='A')
other7 = pd.period_range('1998-01-01', freq='A', periods=8)
expected7 = pd.PeriodIndex(['2007', '2006'], freq='A')
for rng, other, expected in [(rng1, other1, expected1),
(rng2, other2, expected2),
(rng3, other3, expected3),
(rng4, other4, expected4),
(rng5, other5, expected5),
(rng6, other6, expected6),
(rng7, other7, expected7), ]:
result_difference = rng.difference(other, sort=sort)
if sort is None:
expected = expected.sort_values()
tm.assert_index_equal(result_difference, expected)